A) \[N{{i}^{2+}}\]
B) \[S{{c}^{3+}}\]
C) \[C{{u}^{+}}\]
D) \[Z{{n}^{2+}}\]
Correct Answer: A
Solution :
Key Idea: The ions having unpaired electrons are paramagnetic. The, ions having paired electrons are diamagnetic. [a] \[N{{i}^{2+}}=1{{s}^{2}},2{{s}^{2}},2{{p}^{6}},3{{s}^{2}},3{{p}^{6}},4{{s}^{0}},3{{d}^{8}}\] \[\therefore \] It has 2 unpaired electrons and is paramagnetic. [b] \[S{{c}^{3+}}=1{{s}^{2}},2{{s}^{2}},2{{p}^{6}},3{{s}^{2}},3{{p}^{6}},4{{s}^{0}},3{{d}^{0}}\] \[\therefore \] It has no unpaired electrons and is diamagnetic. [c] \[C{{u}^{+}}=1{{s}^{2}},2{{s}^{2}},2{{p}^{6}},3{{s}^{2}},3{{p}^{6}},4{{s}^{0}},3{{d}^{10}}\] It has no unpaired electrons and is diamagnetic. [d] \[Z{{n}^{2+}}=1{{s}^{2}},2{{s}^{2}},2{{p}^{6}},3{{s}^{2}},3{{p}^{6}},4{{s}^{0}},3{{d}^{10}}\] \[\therefore \] It has no unpaired electrons and is diamagnetic.You need to login to perform this action.
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