A) 35.25
B) 35.45
C) 36.25
D) 36.45
Correct Answer: B
Solution :
Key Idea: At. wt. of chlorine \[=\frac{Abundance\,\,\times \,\,mass+Abundance\times mass}{100}\] Given, abundance of \[C{{l}^{35+}}\] isotope = 75.53% Mass of \[C{{l}^{35}}\] isotope = 34.97 Abundance of \[C{{l}^{37}}\] isotope = 24.47% Mass of \[C{{l}^{37}}\] isotope = 36.95 \[\therefore \] At. wt. of chlorine \[=\frac{34.97\times 75.53+24.47\times 36.95}{100}\] \[=\frac{3545.45}{100}\] = 35.45You need to login to perform this action.
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