A) \[400\,\,\Omega \]
B) \[900\,\,\Omega \]
C) \[1100\,\,\Omega \]
D) \[1000\,\,\Omega \]
Correct Answer: B
Solution :
Resistance added to galvanometer is \[R=\frac{V}{{{i}_{g}}}-G\] or \[R=\frac{V}{{{i}_{g}}}-100\] \[\Rightarrow \] \[R+100=\frac{V}{{{i}_{g}}}\] ... (i) and \[R+1000=\frac{2V}{{{i}_{g}}}-100\] \[\Rightarrow \] \[R+1100=\frac{2V}{{{i}_{g}}}\] ... (ii) Dividing Eq. (ii) by Eq. (i), we get \[\frac{R+1100}{R+100}=2\] or \[R+1100=2\,R+200\] or \[R=900\,\,\Omega \]You need to login to perform this action.
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