A) neutral
B) basic
C) acidic
D) amphoteric
Correct Answer: A
Solution :
Key Idea: Write hydrolysis reaction and then compare \[{{K}_{a}}\] and \[{{K}_{b}}\] to decide nature of resulting solution. \[\underset{\begin{smallmatrix} ammonium \\ acetate \end{smallmatrix}}{\mathop{C{{H}_{3}}COON{{H}_{4}}}}\,+{{H}_{2}}O\underset{acetic\text{ }acid}{\mathop{C{{H}_{3}}COOH}}\,\] \[\underset{\begin{smallmatrix} ammonium \\ hydroxide \end{smallmatrix}}{\mathop{+\text{ }N{{H}_{4}}OH}}\,\] Given \[{{K}_{a}}\] for \[C{{H}_{3}}COOH=1.8\times {{10}^{-5}}\] \[{{K}_{b}}\], for \[N{{H}_{4}}OH=1.8\times {{10}^{-5}}\] \[\because \] value of \[{{K}_{a}}\] and \[{{K}_{b}}\]is same. \[\therefore \] solution is neutral.You need to login to perform this action.
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