A) 1.2V
B) 2.6V
C) 4.8 V
D) 9.6 V
Correct Answer: C
Solution :
Key Idea: In parallel combination of two resistors potential drop across each is same. In the given circuit, 30 and 6 0 resistors are in parallel, so potential drops across them will be equal. Let \[{{i}_{1}}\] and \[{{i}_{2}}\] currents are flowing in \[3\,\Omega \] and\[6\,\Omega \] respectively. \[\therefore \] \[3\,{{i}_{1}}=6\,{{i}_{2}}\] But \[{{i}_{1}}=0.8\,A\] (given) \[\therefore \] \[3\times 0.8=6{{i}_{2}}\] \[\Rightarrow \] \[{{i}_{2}}=\frac{3\times 0.8}{6}=0.4\,A\] Net current through the circuit \[i={{i}_{1}}+{{i}_{ & 2}}\] \[=0.8+0.4=12.\,A\] This current will flow through \[4\,\,\Omega \] resistor. So, potential drop across \[4\,\,\Omega \]. resistor is \[V=iR=1.2\times 4=4.8\,V\].You need to login to perform this action.
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