A) -200 cal
B) -300 cal
C) +200 cal
D) +300 cal
Correct Answer: A
Solution :
Key Idea: From first law of thermodynamic. \[\Delta \,E=q+W\] Given \[q=+300\]cal (\[\because \] heat is absorbed) \[W=-500\] cal (\[\because \] work is done on surroundings). \[\therefore \] \[\Delta \,E=q+W\] \[=300+(-500)\] \[=-200\] cal.You need to login to perform this action.
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