A) 125 m/s
B) 250 m/s
C) 500 m/s
D) 1000 m/s
Correct Answer: C
Solution :
A normal mode of an oscillating system is a motion in which all particles of the system move sinusoidally with the same frequency. In general, pth mode of a string fixed at ends has frequency \[n=\frac{p\,v}{2\,l}\] p = 1, 2, 3, ? where v is velocity of wave and \[l\] is length of string. In fourth normal mode, \[p=4\] \[\therefore \] \[n=\frac{4v}{2\,l}\] Given, \[n=500\,Hz,\,l=2\,m\] Hence, \[500=\frac{4\,v}{2\times 2}\] or \[v=\frac{500\times 4}{4}=500\,m/s\]You need to login to perform this action.
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