A) \[[Ne]\,3{{s}^{2}}3{{p}^{6}}3{{d}^{1}}4{{s}^{2}}\]
B) \[[Ne]\,3{{s}^{2}}3{{p}^{6}}3{{d}^{2}}4{{s}^{1}}\]
C) \[[Ne]\,3{{s}^{2}}3{{p}^{6}}3{{d}^{5}}4{{s}^{1}}\]
D) \[[Ne]\,3{{s}^{2}}3{{p}^{6}}4{{s}^{2}}3{{d}^{4}}\]
Correct Answer: C
Solution :
Key Idea: Atomic number of Cr = 24 and its configuration is \[1{{s}^{2}},2{{s}^{2}},2{{p}^{6}},3{{s}^{2}},3{{p}^{6}},4{{s}^{1}},3{{d}^{5}}\]or \[[Ne]\,\,3{{s}^{2}},3{{p}^{6}},3{{d}^{5}},4{{s}^{1}}\] because exactly full filled orbitals are more stable than nearly fulfilled orbitals.
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