A) \[1\,\mu F\]
B) \[2\,\mu F\]
C) \[4\,\mu F\]
D) \[8\,\mu F\]
Correct Answer: A
Solution :
The two capacitors each of value 1.5 \[\mu F\] are in parallel, so their equivalent capacitance. \[{{C}_{1}}=1.5+1.5=3\,\mu F\] Now, three capacitors each of value 3 \[\mu F\] are in series. Hence, their equivalent capacitance is given by \[\frac{1}{C}=\frac{1}{3}+\frac{1}{3}+\frac{1}{3}\] or \[\frac{1}{C}=\frac{3}{5}\] or \[C=1\,\,\mu F\]You need to login to perform this action.
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