A) -75.3kJ
B) +57.3kJ
C) -57.3kJ
D) + 75.3kJ
Correct Answer: C
Solution :
Key Idea: The heat of neutralization of strong acid and strong base is constant because it is infact heat of formation of water by \[{{H}^{+}}\] and\[O{{H}^{-}}\]. Its value is almost equal to - 57.3 kJ.You need to login to perform this action.
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