A) 0.56 cm
B) 1.35 cm
C) 0.41 cm
D) 2.32 cm
Correct Answer: C
Solution :
Key Idea : At the same level in the two limbs of a U-tube, pressure is same. On pouring water on left side, mercury rises x cm (say) from its previous level in the right limb of 17-tube creating a difference of levels of mercury by 2x cm. Equating pressures at A and B, we get \[{{P}_{A}}={{P}_{B}}\] \[\therefore \] \[11.2\times {{10}^{-2}}\times {{\rho }_{water}}\times g=2x\times {{\rho }_{mercury}}\times g\] \[\Rightarrow \] \[11.2\times {{10}^{-2}}\times 1000\,\,kg/{{m}^{3}}\] \[=2x\times 13600\times kg/{{m}^{3}}\] \[\Rightarrow \] \[x=\frac{11.2\times {{10}^{-2}}\times 1000\,\,m}{2\times 13600}\] = 0.41 cmYou need to login to perform this action.
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