A) \[{{n}_{A}}={{n}_{B}}\]
B) \[{{n}_{A}}>{{n}_{B}}\]
C) \[{{n}_{A}}<{{n}_{B}}\]
D) either [b] or [c] depending on the ratio of their diameters
Correct Answer: C
Solution :
In the fundamental mode of vibration \[\frac{\lambda }{4}=(l+0.3\,d)\] where 0.3d is the necessary end correction. Frequency of vibration \[n=\frac{v}{\lambda }=\frac{v}{4(l+0.3\,d)}\] As \[l\] is same for both pipes, wider pipe will resonate at a lower frequency, i.e., \[{{n}_{A}}<{{n}_{B}}\].You need to login to perform this action.
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