A) 17.35 MeV
B) 18.06 MeV
C) 177.35 MeV
D) 170.35 MeV
Correct Answer: A
Solution :
Key Idea The total energy released in reaction (Q) is equal to the difference in kinetic energy of the final particles and of initial particles. The total mass of the initial particles \[{{m}_{i}}=1.007825+7.016004\] \[=8.023829\,\,u\] and the total mass of final particles \[{{m}_{f}}=2\times 4.002603\] = 8.005206 u Difference between initial and final mass of particles \[\Delta m={{m}_{i}}-{{m}_{i}}=8.023829-8.005206\] = 0.018623 u The Q-value is given by \[Q=(\Delta m){{c}^{2}}\] \[=0.018623\times 931.5\] = 17.35 MeVYou need to login to perform this action.
You will be redirected in
3 sec