A) \[2\times {{10}^{-2}}A-m\]
B) \[5\times {{10}^{-2}}A-m\]
C) 2 A-m
D) 5 A-m
Correct Answer: A
Solution :
\[\tau =MB\,\sin \theta \] \[\Rightarrow \]\[\tau (mL)B\sin \theta \] \[\Rightarrow \] \[25\times {{10}^{-6}}=(m\times 5\times {{10}^{-2}})\times 5\times {{10}^{-2}}\times \sin {{30}^{o}}\]. \[\Rightarrow \] \[m=2\times {{10}^{-2}}A-m\]
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