A) 1.52
B) 0.995
C) 190
D) 9
Correct Answer: D
Solution :
\[\frac{{{E}_{Hydroxide}}}{{{E}_{metal}}+{{E}_{O{{H}^{-}}}}}>\frac{{{E}_{oxide}}}{{{E}_{metal}}+{{E}_{O}}}\] \[\frac{1.520}{E+17}=\frac{0.995}{E+8}\] or \[E=9\]You need to login to perform this action.
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