BCECE Medical BCECE Medical Solved Papers-2009

  • question_answer
    The de-Broglie wavelength of a neutron at \[{{927}^{o}}C\] is \[\lambda \]. What will be its wavelength at\[{{27}^{o}}C\]?

    A)  \[\frac{\lambda }{2}\]                 

    B)  \[\lambda \]

    C)  \[2\lambda \]                

    D)  \[4\lambda \]

    Correct Answer: A

    Solution :

    de-Broglie wavelength \[\lambda \propto \frac{1}{\sqrt{T}}\]                 \[\frac{{{\lambda }_{1}}}{{{\lambda }_{2}}}\sqrt{\frac{{{T}_{1}}}{{{T}_{2}}}}\]                 \[\frac{{{\lambda }_{1}}}{{{\lambda }_{2}}}\sqrt{\frac{273+927}{273+27}}=\sqrt{\frac{1200}{300}}=2\] or \[{{\lambda }_{2}}=\frac{{{\lambda }_{1}}}{2}\]


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