A telescope has an objective of focal length 100 cm and an eye-piece of focal length 5 cm. What is the magnifying power of the telescope when it is in normal adjustment?
A) 0.2
B) 2.0
C) 20
D) 200
Correct Answer:
C
Solution :
The magnifying power of the telescope in normal adjustment \[m=\frac{{{f}_{0}}}{{{f}_{e}}}=\frac{100}{5}=20\]