A) Zero
B) \[\frac{mgl}{4}\]
C) \[\frac{mgl}{2}\]
D) \[mgl\]
Correct Answer: C
Solution :
Vertical height \[=h=l\,\cos {{60}^{o}}\] and potential energy = mgh \[mgl\cos {{60}^{o}}\] \[=\frac{mgl}{2}\]You need to login to perform this action.
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