A) Fe
B) Cu
C) Zn
D) Hg
Correct Answer: C
Solution :
Zinc (Zn) being a moderately reactive metal, gives \[{{H}_{2}}\] with acids as well as \[NaOH\]. \[Zn+2HCl\xrightarrow{{}}ZnC{{l}_{2}}+{{H}_{2}}\] \[Zn+NaOH\xrightarrow{{}}\underset{sodium\text{ }zincate}{\mathop{N{{a}_{2}}Zn{{O}_{2}}}}\,+{{H}_{2}}\]You need to login to perform this action.
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