A) zero
B) 1
C) -1
D) 2
Correct Answer: C
Solution :
For angular momentum to be conserved \[{{\vec{T}}_{ext}}=0\] \[\Rightarrow \] \[\frac{a}{2}=\frac{3}{-6}=\frac{6}{-12}\] \[\Rightarrow \] \[a=\frac{2\times 3}{-6}=-1\]You need to login to perform this action.
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