A) 28.4 MeV
B) 20.8 MeV
C) 27.3 MeV
D) 14.2 MeV
Correct Answer: A
Solution :
Mass defect. \[\Delta m=2({{m}_{n}}+{{m}_{p}})-{{m}_{He}}\] (\[\because \] helium nucleus has two protons and two neutrons) \[\therefore \] \[\Delta m=2\,(1.0087+1.0073)-4.0015\] \[=4.032-4.0015=0.0305\] Binding energy, \[{{E}_{B}}=\Delta m\times 931\,MeV\] \[=0.0305\times 931\] = 28.4 MeVYou need to login to perform this action.
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