Three point masses, each of mass m are placed at the comers of an equilateral triangle of side cl The moment of inertia of this system about an axis along one side of the triangle is
A) 3 \[m{{a}^{2}}\]
B) \[m{{a}^{2}}\]
C) 3 \[m{{a}^{2}}\]
D) 3 \[m{{a}^{2}}\]
Correct Answer:
C
Solution :
Moment of inertia of system about side AB is \[I=m{{(0)}^{2}}+m{{(0)}^{2}}+m{{\left( \frac{\sqrt{3}}{2}a \right)}^{2}}\] \[=\frac{3}{4}m{{a}^{2}}\]