A) (1/4) fold
B) (3/4) fold
C) (5/4) fold
D) (9/4) fold
Correct Answer: D
Solution :
Two waves superimpose in phase. Hence, resultant amplitude \[=\sqrt{I}+\sqrt{I/4}=\frac{3}{2}\sqrt{I}\] So, resultant intensity \[={{\left( \frac{3}{2}\sqrt{I} \right)}^{2}}=\frac{9}{4}I=\frac{9}{4}\] foldYou need to login to perform this action.
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