A) \[-\frac{Q}{2}\]
B) \[-\frac{Q}{4}\]
C) \[+\frac{Q}{4}\]
D) \[+\frac{Q}{2}\]
Correct Answer: B
Solution :
For equilibrium of Q \[\frac{Qq}{4\pi {{\varepsilon }_{0}}{{\left( \frac{l}{2} \right)}^{2}}}+\frac{{{Q}^{2}}}{4\pi \,{{\varepsilon }_{0}}\,{{l}^{2}}}=0\] \[\Rightarrow \] \[4q+Q=0\] \[\Rightarrow \] \[q=\frac{-Q}{4}\] Here, we are asked to calculate equilibrium for system. In this system q is already in equilibrium. So, we are calculating equilibrium condition for Q.You need to login to perform this action.
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