A) \[62.5\times {{10}^{-6}}\]
B) \[6.25\times {{10}^{-4}}\]
C) \[15.625\times {{10}^{-6}}\]
D) \[3.125\times {{10}^{-6}}\]
Correct Answer: A
Solution :
Given, solubility of \[A{{g}_{2}}S{{O}_{4}}=2.5\times {{10}^{-2}}M\] Let the solution of \[A{{g}_{2}}S{{O}_{4}}=x\,mol/L\] \[A{{g}_{2}}S{{O}_{4}}\xrightarrow{{}}2A{{g}^{+}}+SO_{4}^{2-}\] \[\underset{x}{\mathop{A{{g}_{2}}S{{O}_{4}}}}\,\xrightarrow{{}}2A{{g}^{+}}+SO_{4}^{2-}\] \[{{K}_{sp=}}{{[A{{g}^{+}}]}^{2x}}{{[SO_{4}^{2-}]}^{x}}\] \[={{(2x)}^{2}}(x)\] \[=4{{x}^{3}}\] \[=4\times {{(2.5\times {{10}^{-2}})}^{3}}\] \[=62.5\times {{10}^{-6}}\]
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