A) 3s
B) 4f
C) 5p
D) 6s
Correct Answer: B
Solution :
The value of n decides the shell of electrons. The value of \[l\] decides the orbital; \[l=0\] is s, \[l=1\] is p, \[l=2\]is d and \[l=3\] is \[f\] Given, \[n=4,\,l=3,\,m-2,\,s=-\frac{1}{2}\] \[\therefore \] It is \[4f\] orbital/.You need to login to perform this action.
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