A) 400 m/s
B) 421 m/s
C) 500 m/s
D) 600 m/s
Correct Answer: C
Solution :
Most probable velocity, \[{{v}_{mp}}=\sqrt{\frac{2kT}{m}}\] \[=\sqrt{\frac{2RT}{m}}=\sqrt{\frac{8.31\times 421}{28\times {{10}^{-3}}}}\] = 499.89 = 500 m/sYou need to login to perform this action.
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