A) 10 mL
B) 5 mL
C) 20 mL
D) 30 mL
Correct Answer: A
Solution :
10 mL 0.1 N \[AgN{{O}_{3}}\] will react with 10 mL of 0.1\[NHCl\]. \[\therefore \] 0.1 \[NHCl\] left = 10mL Thus, it will neutralise 10 mL of 0.1 N NaOH.You need to login to perform this action.
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