A) 2.9 cm
B) 3.9 cm
C) 2.35cm
D) 2cm
Correct Answer: C
Solution :
Radius of circular path, \[r=\frac{mv}{Bq}\] \[=\frac{v}{\left( \frac{e}{m} \right)B}=\frac{6\times {{10}^{7}}}{1.7\times {{10}^{11}}1.5\times {{10}^{-2}}}\] = 2.35 cmYou need to login to perform this action.
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