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BCECE Medical BCECE Medical Solved Papers-2012

  • question_answer
    Four plates of same area of cross-section are joined as shown in figure. The distance between each plate is d. The equivalent capacity between A and B will be

    A)  \[\frac{2\,{{\varepsilon }_{0}}\,A}{d}\]    

    B)  \[\frac{{{\varepsilon }_{0}}\,A}{d}\]

    C)  \[\frac{3{{\varepsilon }_{0}}\,A}{d}\]

    D)  \[\frac{3{{\varepsilon }_{0}}\,A}{2\,d}\]

    Correct Answer: C

    Solution :

    The given arrangement is equivalent to the parallel combination of three identical capacitors. Hence, equivalent capacitance \[=3C=\frac{3\,{{\varepsilon }_{0}}A}{d}\]


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