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  3. BCECE Medical

BCECE Medical BCECE Medical Solved Papers-2012

  • question_answer
    For the transistor circuit shown in figure, if\[\beta =100\], voltage drop across emitter and base is 0.7 V, then the value of \[{{V}_{CE}}\] will be

    A)  Zero           

    B)  5 V

    C)  10 V           

    D)  13 V

    Correct Answer: D

    Solution :

    We have, \[{{i}_{b}}=\frac{5-0.7}{8.6}=0.5\,mA\] \[\therefore \]  \[{{i}_{c}}={{\beta }_{ib}}=100\times 0.5\,\,mA\]                 = 50 mA By using                 \[{{V}_{CE}}={{V}_{CC}}-{{i}_{C}}{{R}_{L}}\]                 \[=18-50\times {{10}^{-3}}\times 100\] = 18 - 15 = 13 V


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