A) \[q=w=500\,J,\,\,\Delta U=0\]
B) \[q=\Delta U=500\,J,w=0\]
C) \[q=W=500\,J,\Delta U=0\]
D) \[\Delta U=0,\,\,q=W=-500\,J\]
Correct Answer: B
Solution :
As we know that \[\Delta H=\Delta E+p\Delta V\] When \[\Delta V=0\] \[\therefore \] \[\Delta H=\Delta E\] From first law of thermodynamics \[\Delta U=q+W\] In the given problem, \[\Delta H=500\,J\] \[-W=-p\Delta V,\Delta V=0\] So, \[\Delta U=q=500\,J\]You need to login to perform this action.
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