A) T
B) 3T
C) 3V3T
D) 9T
Correct Answer: A
Solution :
For a nearest satellite, the period of revolution is \[T=2\pi \sqrt{\frac{{{R}^{3}}}{GM}}\] \[=2\pi \sqrt{\frac{{{R}^{3}}}{G\frac{4}{3}\pi {{R}^{3}}\rho }}\] \[T\propto \sqrt{\frac{1}{\rho }}\] i.e. the period of revolution depends upon the density of the planet. Here, the density of the planets is same, therefore time period will be same.You need to login to perform this action.
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