A) 9.25
B) 4.75
C) 3.75
D) 8.25
Correct Answer: B
Solution :
Solution of \[N{{H}_{4}}OH\] and \[N{{H}_{4}}Cl\] acts as a basic buffer solution. For basic buffer solution, \[pOH=p{{K}_{b}}+\log \frac{[Salt]}{[Base]}\] \[pOH=14-pH=14-9.25=4.75\] \[4.75=p{{K}_{b}}+\log \frac{0.1}{0.1}\] \[p{{K}_{b}}=4.75\]You need to login to perform this action.
You will be redirected in
3 sec