A) 50.5 m
B) 91.5 m
C) 86.6 m
D) 100 m
Correct Answer: C
Solution :
Total time of flight \[=\frac{2u\sin \theta }{g}=\frac{2\times 50\times 1}{2\times 10}=5\,s\] Time to cross the wall = 3 s \[\therefore \] Time in air after crossing the wall = (5 - 3) = 2 s So, distance travelled beyond the wall \[=(u\cos \theta )\,t\] \[=50\times \frac{\sqrt{3}}{2}\times 2=86.6\,m\]You need to login to perform this action.
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