A) 3 cm
B) 16 cm
C) 12 cm
D) 24 cm
Correct Answer: A
Solution :
Rise in capillary, \[h=\frac{2T\cos \theta }{rdg}\] \[\therefore \] \[\frac{{{h}_{2}}}{{{h}_{1}}}=\frac{{{T}_{2}}}{{{T}_{1}}}\times \frac{\cos \theta }{\cos {{\theta }_{1}}}\times \frac{{{d}_{1}}}{{{d}_{2}}}\times \frac{{{r}_{1}}}{{{r}_{2}}}\] \[\frac{{{h}_{2}}}{{{h}_{1}}}=\frac{140}{70}\times \frac{\cos {{60}^{o}}}{\cos {{0}^{o}}}\times \frac{1}{2}\times 1\] \[{{h}_{2}}=\frac{{{h}_{1}}}{2}=3\,cm\]
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