A) Zero
B) 5 V
C) 10 V
D) 13 V
Correct Answer: D
Solution :
We have, \[{{i}_{b}}=\frac{5-0.7}{8.6}=0.5\,mA\] \[\therefore \] \[{{i}_{c}}={{\beta }_{ib}}=100\times 0.5\,\,mA\] = 50 mA By using \[{{V}_{CE}}={{V}_{CC}}-{{i}_{C}}{{R}_{L}}\] \[=18-50\times {{10}^{-3}}\times 100\] = 18 - 15 = 13 VYou need to login to perform this action.
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