A) Silicon exhibits 4 coordination number in its compounds
B) Bond energy of \[{{F}_{2}}\] is less than \[C{{l}_{2}}\]
C) Mn(III) oxidation state is more stable than Mn(II) in aqueous state
D) Elements of 15th group shows only +3 and +5 oxidation states
Correct Answer: B
Solution :
Bond energy of \[{{F}_{2}}\] is less than \[C{{l}_{2}}\] because in \[{{F}_{2}}\] molecule, electron-electron repulsion of 2p-orbital of two fluorine atoms is maximum in comparison to the repulsion of 3p-orbitals of two chlorine atoms. So, less amount of energy is required to break the bond of \[{{F}_{2}}\] in comparison to \[C{{l}_{2}}\].You need to login to perform this action.
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