BCECE Medical BCECE Medical Solved Papers-2013

  • question_answer
    One turn of the helix in a B-form DNA is approximately

    A)  20 nm

    B)  0.34 nm

    C)  3.4 nm            

    D)  2 nm

    Correct Answer: C

    Solution :

    B-DNA is helical structure with 20A diameter and the distance between the two base pairs is 3.4 \[\overset{o}{\mathop{A}}\,\] and there are 10 base pairs in each turn or pitch (one round). Hence, one turn of the helix is approximately 34\[\overset{o}{\mathop{A}}\,\] or 3.4 nm (10 \[\overset{o}{\mathop{A}}\,\]= 1.0 nm)


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