BCECE Medical BCECE Medical Solved Papers-2013

  • question_answer
    Force acting upon a charged particle kept between the plates of changed capacitor is F. If one of the plates of the capacitor is removed force acting on the same particle will become

    A)  0 

    B)  F

    C)  \[\frac{F}{2}\]

    D)  2F

    Correct Answer: C

    Solution :

    Electric field between the oppositely charged plates of a capacitor is twice that due to one : plate Hence, when one, plate is removed, the electric force reduces to half of its earlier value.


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