A) \[{{B}_{3}}{{N}_{3}}{{H}_{6}}\]
B) \[{{B}_{2}}{{H}_{6}}\]
C) \[NaBC{{l}_{4}}\]
D) BN
Correct Answer: A
Solution :
\[3BC{{l}_{3}}+3N{{H}_{4}}Cl\xrightarrow[{{C}_{6}}{{H}_{5}}Cl]{{{140}^{o}}C}{{B}_{3}}{{N}_{3}}{{H}_{3}}C{{l}_{3}}\] \[\xrightarrow{NaB{{H}_{4}}}\underset{\begin{smallmatrix} borazine\text{ }or \\ inorganic\text{ }benzene \end{smallmatrix}}{\mathop{{{B}_{3}}{{N}_{3}}{{H}_{6}}}}\,\]
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