A) \[2\,p\tan \theta \]
B) \[2\,p\sin \theta \]
C) \[2\,p\cos \theta \]
D) 2p
Correct Answer: B
Solution :
\[\left| ({{P}_{f}}-{{P}_{i}} \right|=\] Change in momentum \[=\sqrt{{{P}^{2}}+{{P}^{2}}+2P\,.\,P\cos \,\,(\pi -2\theta )}\] \[=P\sqrt{2+2(-\cos \theta )}\] \[=P\sqrt{2\,\,(2{{\sin }^{2}}\theta )}\] \[=2P\,\,\sin \,\,\theta \]You need to login to perform this action.
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