A) 2.52
B) 2.20
C) 2.35
D) 2.01
Correct Answer: B
Solution :
As the size of atom (element) increases, energy required to overcome the attractive force on outermost electron decreases. Li, Na, K and Rb are the members of same group and have the following order of size \[Li<Na<K<Rb\] Thus, the energy in case of K is intermediate of Rb and Na, i.e., \[2.30<K<2.09\] or the energy for K is 2.20 eV.You need to login to perform this action.
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