A) \[\frac{\sqrt{{{E}_{K}}}}{2}\]
B) \[\frac{1}{\sqrt{2{{E}_{K}}}}\]
C) \[\frac{1}{\sqrt{{{E}_{K}}}}\]
D) \[\frac{\sqrt{3{{E}_{K}}}}{2}\]
Correct Answer: C
Solution :
\[{{\lambda }_{photon}}=\frac{hc}{{{E}_{k}}}\] \[{{\lambda }_{electron}}=\frac{hc}{\sqrt{2m{{E}_{k}}}}\] \[\frac{{{\lambda }_{photon}}}{{{\lambda }_{electron}}}=\frac{1}{\sqrt{{{E}_{k}}}}\]
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