BCECE Medical BCECE Medical Solved Papers-2014

  • question_answer Given that \[dE=TdS-pdV\] and \[H=E+pV\]. Which one of the following relations is true?

    A)  \[dH=TdS-Vdp\]

    B)  \[dH=SdT+Vdp\]

    C)  \[dH=-SdT-Vdp\]  

    D)  \[dH=dE-pdV\]

    Correct Answer: A

    Solution :

    Given,                 \[dE=TdS-pdV\] ... (i)                 \[H=E+pV\] ... (ii) Differentiating Eq. (ii)                 \[dH=dE+pdV+Vdp\] ... (iii) From Eq.,(i) and (iii), we get \[dH=TdS-Vdp\]

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