A) Moissan boron is amorphous
B) The reaction between boron and concentrated \[HN{{O}_{3}}\] gives \[{{N}_{2}}O\]
C) Amorphous boron on heating with oxygen forms \[{{B}_{2}}{{O}_{3}}\]
D) Boron is a non-conductor of electricity
Correct Answer: B
Solution :
Boron reacts with concentrated \[HN{{O}_{3}}\] to give orthoboric acid and nitrogen dioxide. \[B+3HN{{O}_{3}}\xrightarrow{{}}{{H}_{3}}B{{O}_{3}}+3N{{O}_{2}}\]
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