I. \[{{H}_{3}}P{{O}_{4}}+{{H}_{2}}O\xrightarrow{{}}{{H}_{3}}{{O}^{+}}+{{H}_{2}}PO_{4}^{-}\] |
II. \[{{H}_{3}}PO_{4}^{-}+{{H}_{2}}O\xrightarrow{{}}HPO_{4}^{2-}+{{H}_{3}}{{O}^{+}}\] |
III. \[{{H}_{3}}PO_{4}^{-}+O{{H}^{-}}\xrightarrow{{}}{{H}_{3}}P{{O}_{4}}+{{O}^{2-}}\] |
A) II only
B) I and II
C) III only
D) I only
Correct Answer: A
Solution :
Only in reaction (II) \[{{H}_{2}}PO_{4}^{-}\], gives \[{{H}^{+}}\] to \[{{H}_{2}}O\], thus behaves as an acid.You need to login to perform this action.
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