A | B | |
I. | \[0.1\text{ }M\,KCl\] | \[0.2\text{ }M\,KCl\] |
II. | \[~0.1%\,(m/V)\,NaCl\] | \[10%\,(m/V)\,NaCl\] |
III. | \[18\,g{{L}^{-1}}glucose\] | \[34.2\text{ }g{{L}^{-1}}\text{ }sucrose\] |
IV. | \[20%\text{ (}m/V)\,glucose\] | \[10%\text{ (}m/V)\,glucose\] |
A) I only
B) III only
C) IV only
D) II only
Correct Answer: B
Solution :
Isotonic solution have same molarty. Molarity of 18 g glucose \[=\frac{18}{180}/\frac{100}{100}=0.1\] Molarity of 34.2 g sucrose \[=\frac{34.2}{342}/\frac{1000}{1000}=0.1\] The concentration of \[18\,g\,{{L}^{-1}}\] glucose is same to \[34.2\,g{{L}^{-1}}\] sucrose.You need to login to perform this action.
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