• # question_answer The empirical formula of a non-electrolyte is$C{{H}_{2}}O$. A solution containing 6g of the compound exerts the same osmotic pressure as that of 0.05 M glucose solution at the same temperature. The molecular formula of the compound is A)  ${{C}_{2}}{{H}_{4}}{{O}_{2}}$ B)  ${{C}_{3}}{{H}_{6}}{{O}_{3}}$ C)  ${{C}_{5}}{{H}_{10}}{{O}_{5}}$ D)  ${{C}_{4}}{{H}_{8}}{{O}_{4}}$

Solutions having same osmotic pressure, at a given temperature, have same concentration. Concentration of compound = concentration of glucose $\frac{6}{M\times 1}=0.05$                 $M=\frac{6}{0.05}=120$ $(C{{H}_{2}}O)=12+2+16=30$          $n=\frac{molecular\text{ }mass}{empirical\text{ }formula\text{ }mass}=\frac{120}{30}=4$ Hence, molecular formula ${{(C{{H}_{2}}O)}_{4}}={{C}_{4}}{{H}_{8}}{{O}_{4}}$