A) 3
B) 4
C) 2
D) 1
Correct Answer: B
Solution :
The electronic configuration of \[{{M}^{x+}}(Z=25)\] is \[1{{s}^{2}},2{{s}^{2}},2{{p}^{6}},3{{s}^{2}},3{{p}^{6}},3{{d}^{5}},4{{s}^{2}}\] Magnetic moment \[=\sqrt{n\,(n+2)}\,BM\] \[=\sqrt{5\,(5+2)}\,BM=\sqrt{35}\,BM\] Given, magnetic moment \[=\sqrt{15}\,BM=\sqrt{3\,(3+2)}\,BM\] Hence, unpaired electrons = 3 \[\therefore \] The oxidation number \[x\] is 4.You need to login to perform this action.
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